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Simplifying 24b2 + 25 = b4 Reorder the terms: 25 + 24b2 = b4 Solving 25 + 24b2 = b4 Solving for variable 'b'. Combine like terms: b4 + -1b4 = 0 25 + 24b2 + -1b4 = 0 Factor a trinomial. (25 + -1b2)(1 + b2) = 0 Factor a difference between two squares. ((5 + b)(5 + -1b))(1 + b2) = 0Subproblem 1
Set the factor '(1 + b2)' equal to zero and attempt to solve: Simplifying 1 + b2 = 0 Solving 1 + b2 = 0 Move all terms containing b to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + b2 = 0 + -1 Combine like terms: 1 + -1 = 0 0 + b2 = 0 + -1 b2 = 0 + -1 Combine like terms: 0 + -1 = -1 b2 = -1 Simplifying b2 = -1 The solution to this equation could not be determined. This subproblem is being ignored because a solution could not be determined.Subproblem 2
Set the factor '(5 + b)' equal to zero and attempt to solve: Simplifying 5 + b = 0 Solving 5 + b = 0 Move all terms containing b to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + b = 0 + -5 Combine like terms: 5 + -5 = 0 0 + b = 0 + -5 b = 0 + -5 Combine like terms: 0 + -5 = -5 b = -5 Simplifying b = -5Subproblem 3
Set the factor '(5 + -1b)' equal to zero and attempt to solve: Simplifying 5 + -1b = 0 Solving 5 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + -1b = 0 + -5 Combine like terms: 5 + -5 = 0 0 + -1b = 0 + -5 -1b = 0 + -5 Combine like terms: 0 + -5 = -5 -1b = -5 Divide each side by '-1'. b = 5 Simplifying b = 5Solution
b = {-5, 5}
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